Deleting Shapefile Features

Sometimes, usually as a server-based operation, you need to delete all of the features in a shapefile. All you want left is the shapefile type, the dbf schema, and maybe the overall bounding box. This shapefile stub can then be updated by other processes. Pyshp currently doesn't have an explicit "delete" method. But because pyshp converts everything to native Python data types (strings, lists, dicts, numbers) you can usually manipulate things fairly easily. The solution is very similar to merging shapefiles but instead you are writing back to the same file instead of a new copy. There's only one hitch in this operation resulting from a minor difference in the pyshp Reader and Writer objects. In the reader the "bbox" property returns a static array of [xmin, ymin, xmax, ymax]. The Writer also has a "bbox" property but it is a method that is called when you save the shapefile. The Writer calculates the bounding box on the fly by reading all of the shapes just before saving. But in this case there are no shapes so the method would throw an error. So what we do is just override that method with a lambda function to return whatever bbox we want whether it be the original bbox or a made up one.

import shapefile 
# Read the shapefile we want to clear out
r = shapefile.Reader("myshape") 
# Create a Writer of the same type to save out as a blank
w = shapefile.Writer(r.shapeType) 
# This line will give us the same dbf schema 
w.fields = r.fields 
# Use the original bounding box in the header 
w.bbox = lambda: r.bbox 
# Save the featureless, attribute-less shapefile
w.save("myshape") 

Instead of using the original bounding box we could just populate it with 0's and let the update process repopulate it:

w.bbox = lambda: [0.0, 0.0, 0.0, 0.0]

Note coordinates in a shapefile must always be floating-point numbers. Sometimes you may not want to delete all of the features. You may want to select certain features by attribute or using a spatial operation.